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Scientific American Monthly Volume 3

Scientific American Monthly Volume 3

Scientific American Monthly Volume 3.cBooks Group
Scientific American Monthly Volume 3
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Author: Books Group
Page Count: 590 pages
Published Date: 01 Mar 2012
Publisher: Rarebooksclub.com
Publication Country: Miami Fl, United States
Language: Englishhttps://d3by36x8sj6cra.cloudfront.net/assets/images/book/large/9781/2368/9781236892331.jpg
ISBN: 9781130512083
Download Link: Scientific American Monthly Volume 3
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This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1921 Excerpt: ...step is to balance the equation, that is, so choose the coefficients, that the number of atoms of each element on either side of the equation shall be equal. Every teacher and student of chemistry has no doubt experienced some difficulty at times, and very often has consumed much valuable time in this last operation. This, of course, is not the case, when the reactions are simple, since mere inspection will at once suggest the proper coefficients to be placed before each of the factors and products. In proportion, however, as the reaction becomes more complex, inspection becomes more difficult, and the method of trial coefficients must be invoked, which involves a certain amount of guess-work, with the consequent uncertainty and loss of time. When such difficult equations arise, we may use the method, described below, which very often will take the guess out of the problem of balancing chemical equations. The method is based on the principle that a chemical equation conforms in some respects to the algebraic equation, and hence the algebraic process may be legitimately used. This does not mean that all algebraic processes may be used, because the two kinds of equations do not conform in all respects. Let us take as an example the following reaction, in which the required coefficients are indicated by letters: aCrCl, + bNaC3H30L. + cH,0 + dCl = eNaCl + fH.C2Hs02 + gNa, CrO-. Substituting these values in the original equation, we have: CrCl, + SNaCjH.O. + 4H,0 + 3C1 = 6NaCl + SH.CH.O, + Na, CrO Since it is more accurate to write 3C1, than 3C1, the equation may be so corrected by multiplying each coefficient by 2. It sometimes happens that the solution of the simultaneous equations involve fractional values. In such cases the fractions may be got rid of by .

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